6(l+3)=3(2l+6)

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Solution for 6(l+3)=3(2l+6) equation: 



6(l+3)=3(2l+6)

We move all terms to the left:

6(l+3)-(3(2l+6))=0

We multiply parentheses

6l-(3(2l+6))+18=0



We calculate terms in parentheses: -(3(2l+6)), so:

3(2l+6)

We multiply parentheses

6l+18

Back to the equation:

-(6l+18)



We get rid of parentheses

6l-6l-18+18=0

We add all the numbers together, and all the variables

=0

l=0/1

l=0

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