6(m+1)=2(m-5)

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Solution for 6(m+1)=2(m-5) equation: 



6(m+1)=2(m-5)

We move all terms to the left:

6(m+1)-(2(m-5))=0

We multiply parentheses

6m-(2(m-5))+6=0



We calculate terms in parentheses: -(2(m-5)), so:

2(m-5)

We multiply parentheses

2m-10

Back to the equation:

-(2m-10)



We get rid of parentheses

6m-2m+10+6=0

We add all the numbers together, and all the variables

4m+16=0

We move all terms containing m to the left, all other terms to the right

4m=-16

m=-16/4

m=-4

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