6(m+2)+7=5(m-1)

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Solution for 6(m+2)+7=5(m-1) equation: 



6(m+2)+7=5(m-1)

We move all terms to the left:

6(m+2)+7-(5(m-1))=0

We multiply parentheses

6m-(5(m-1))+12+7=0



We calculate terms in parentheses: -(5(m-1)), so:

5(m-1)

We multiply parentheses

5m-5

Back to the equation:

-(5m-5)



We add all the numbers together, and all the variables

6m-(5m-5)+19=0

We get rid of parentheses

6m-5m+5+19=0

We add all the numbers together, and all the variables

m+24=0

We move all terms containing m to the left, all other terms to the right

m=-24

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