6(m+2)-3(4m+4)=48

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Solution for 6(m+2)-3(4m+4)=48 equation: 



6(m+2)-3(4m+4)=48

We move all terms to the left:

6(m+2)-3(4m+4)-(48)=0

We multiply parentheses

6m-12m+12-12-48=0

We add all the numbers together, and all the variables

-6m-48=0

We move all terms containing m to the left, all other terms to the right

-6m=48

m=48/-6

m=-8

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