6(m+2)=13(m-2)-4

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Solution for 6(m+2)=13(m-2)-4 equation: 



6(m+2)=13(m-2)-4

We move all terms to the left:

6(m+2)-(13(m-2)-4)=0

We multiply parentheses

6m-(13(m-2)-4)+12=0



We calculate terms in parentheses: -(13(m-2)-4), so:

13(m-2)-4

We multiply parentheses

13m-26-4

We add all the numbers together, and all the variables

13m-30

Back to the equation:

-(13m-30)



We get rid of parentheses

6m-13m+30+12=0

We add all the numbers together, and all the variables

-7m+42=0

We move all terms containing m to the left, all other terms to the right

-7m=-42

m=-42/-7

m=+6

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