6(m+3)+3m=2(m-3)

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Solution for 6(m+3)+3m=2(m-3) equation: 



6(m+3)+3m=2(m-3)

We move all terms to the left:

6(m+3)+3m-(2(m-3))=0

We add all the numbers together, and all the variables

3m+6(m+3)-(2(m-3))=0

We multiply parentheses

3m+6m-(2(m-3))+18=0



We calculate terms in parentheses: -(2(m-3)), so:

2(m-3)

We multiply parentheses

2m-6

Back to the equation:

-(2m-6)



We add all the numbers together, and all the variables

9m-(2m-6)+18=0

We get rid of parentheses

9m-2m+6+18=0

We add all the numbers together, and all the variables

7m+24=0

We move all terms containing m to the left, all other terms to the right

7m=-24

m=-24/7

m=-3+3/7

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