6(m+3)=2(m+5)

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Solution for 6(m+3)=2(m+5) equation: 



6(m+3)=2(m+5)

We move all terms to the left:

6(m+3)-(2(m+5))=0

We multiply parentheses

6m-(2(m+5))+18=0



We calculate terms in parentheses: -(2(m+5)), so:

2(m+5)

We multiply parentheses

2m+10

Back to the equation:

-(2m+10)



We get rid of parentheses

6m-2m-10+18=0

We add all the numbers together, and all the variables

4m+8=0

We move all terms containing m to the left, all other terms to the right

4m=-8

m=-8/4

m=-2

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