6(m+3)=5(m-2)

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Solution for 6(m+3)=5(m-2) equation: 



6(m+3)=5(m-2)

We move all terms to the left:

6(m+3)-(5(m-2))=0

We multiply parentheses

6m-(5(m-2))+18=0



We calculate terms in parentheses: -(5(m-2)), so:

5(m-2)

We multiply parentheses

5m-10

Back to the equation:

-(5m-10)



We get rid of parentheses

6m-5m+10+18=0

We add all the numbers together, and all the variables

m+28=0

We move all terms containing m to the left, all other terms to the right

m=-28

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