6(m+3)=m-17

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Solution for 6(m+3)=m-17 equation: 



6(m+3)=m-17

We move all terms to the left:

6(m+3)-(m-17)=0

We multiply parentheses

6m-(m-17)+18=0

We get rid of parentheses

6m-m+17+18=0

We add all the numbers together, and all the variables

5m+35=0

We move all terms containing m to the left, all other terms to the right

5m=-35

m=-35/5

m=-7

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