6(m-1)+12=3(3m+5)-2m

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Solution for 6(m-1)+12=3(3m+5)-2m equation: 



6(m-1)+12=3(3m+5)-2m

We move all terms to the left:

6(m-1)+12-(3(3m+5)-2m)=0

We multiply parentheses

6m-(3(3m+5)-2m)-6+12=0



We calculate terms in parentheses: -(3(3m+5)-2m), so:

3(3m+5)-2m

We add all the numbers together, and all the variables

-2m+3(3m+5)

We multiply parentheses

-2m+9m+15

We add all the numbers together, and all the variables

7m+15

Back to the equation:

-(7m+15)



We add all the numbers together, and all the variables

6m-(7m+15)+6=0

We get rid of parentheses

6m-7m-15+6=0

We add all the numbers together, and all the variables

-1m-9=0

We move all terms containing m to the left, all other terms to the right

-m=9

m=9/-1

m=-9

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