6(m-1)+12=3(3m+5)-2m

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Solution for 6(m-1)+12=3(3m+5)-2m equation:



6(m-1)+12=3(3m+5)-2m
We move all terms to the left:
6(m-1)+12-(3(3m+5)-2m)=0
We multiply parentheses
6m-(3(3m+5)-2m)-6+12=0
We calculate terms in parentheses: -(3(3m+5)-2m), so:
3(3m+5)-2m
We add all the numbers together, and all the variables
-2m+3(3m+5)
We multiply parentheses
-2m+9m+15
We add all the numbers together, and all the variables
7m+15
Back to the equation:
-(7m+15)
We add all the numbers together, and all the variables
6m-(7m+15)+6=0
We get rid of parentheses
6m-7m-15+6=0
We add all the numbers together, and all the variables
-1m-9=0
We move all terms containing m to the left, all other terms to the right
-m=9
m=9/-1
m=-9

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