6(m-2)+14=3(m+12)-10

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Solution for 6(m-2)+14=3(m+12)-10 equation: 



6(m-2)+14=3(m+12)-10

We move all terms to the left:

6(m-2)+14-(3(m+12)-10)=0

We multiply parentheses

6m-(3(m+12)-10)-12+14=0



We calculate terms in parentheses: -(3(m+12)-10), so:

3(m+12)-10

We multiply parentheses

3m+36-10

We add all the numbers together, and all the variables

3m+26

Back to the equation:

-(3m+26)



We add all the numbers together, and all the variables

6m-(3m+26)+2=0

We get rid of parentheses

6m-3m-26+2=0

We add all the numbers together, and all the variables

3m-24=0

We move all terms containing m to the left, all other terms to the right

3m=24

m=24/3

m=8

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