6(m-2)+7=3(m+2)-3

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Solution for 6(m-2)+7=3(m+2)-3 equation: 



6(m-2)+7=3(m+2)-3

We move all terms to the left:

6(m-2)+7-(3(m+2)-3)=0

We multiply parentheses

6m-(3(m+2)-3)-12+7=0



We calculate terms in parentheses: -(3(m+2)-3), so:

3(m+2)-3

We multiply parentheses

3m+6-3

We add all the numbers together, and all the variables

3m+3

Back to the equation:

-(3m+3)



We add all the numbers together, and all the variables

6m-(3m+3)-5=0

We get rid of parentheses

6m-3m-3-5=0

We add all the numbers together, and all the variables

3m-8=0

We move all terms containing m to the left, all other terms to the right

3m=8

m=8/3

m=2+2/3

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