6(m-2)=12-(m+3)

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Solution for 6(m-2)=12-(m+3) equation: 



6(m-2)=12-(m+3)

We move all terms to the left:

6(m-2)-(12-(m+3))=0

We multiply parentheses

6m-(12-(m+3))-12=0



We calculate terms in parentheses: -(12-(m+3)), so:

12-(m+3)

determiningTheFunctionDomain
-(m+3)+12

We get rid of parentheses

-m-3+12

We add all the numbers together, and all the variables

-1m+9

Back to the equation:

-(-1m+9)



We get rid of parentheses

6m+1m-9-12=0

We add all the numbers together, and all the variables

7m-21=0

We move all terms containing m to the left, all other terms to the right

7m=21

m=21/7

m=3

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