6(m-2)=3(2-m)

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Solution for 6(m-2)=3(2-m) equation: 



6(m-2)=3(2-m)

We move all terms to the left:

6(m-2)-(3(2-m))=0

We add all the numbers together, and all the variables

6(m-2)-(3(-1m+2))=0

We multiply parentheses

6m-(3(-1m+2))-12=0



We calculate terms in parentheses: -(3(-1m+2)), so:

3(-1m+2)

We multiply parentheses

-3m+6

Back to the equation:

-(-3m+6)



We get rid of parentheses

6m+3m-6-12=0

We add all the numbers together, and all the variables

9m-18=0

We move all terms containing m to the left, all other terms to the right

9m=18

m=18/9

m=2

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