6(m-4)+2(4-5m)=-5(m+8)+10

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Solution for 6(m-4)+2(4-5m)=-5(m+8)+10 equation: 



6(m-4)+2(4-5m)=-5(m+8)+10

We move all terms to the left:

6(m-4)+2(4-5m)-(-5(m+8)+10)=0

We add all the numbers together, and all the variables

6(m-4)+2(-5m+4)-(-5(m+8)+10)=0

We multiply parentheses

6m-10m-(-5(m+8)+10)-24+8=0



We calculate terms in parentheses: -(-5(m+8)+10), so:

-5(m+8)+10

We multiply parentheses

-5m-40+10

We add all the numbers together, and all the variables

-5m-30

Back to the equation:

-(-5m-30)



We add all the numbers together, and all the variables

-4m-(-5m-30)-16=0

We get rid of parentheses

-4m+5m+30-16=0

We add all the numbers together, and all the variables

m+14=0

We move all terms containing m to the left, all other terms to the right

m=-14

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