6(m-4)+2(4-5m)=-5(m+8)+10

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Solution for 6(m-4)+2(4-5m)=-5(m+8)+10 equation:



6(m-4)+2(4-5m)=-5(m+8)+10
We move all terms to the left:
6(m-4)+2(4-5m)-(-5(m+8)+10)=0
We add all the numbers together, and all the variables
6(m-4)+2(-5m+4)-(-5(m+8)+10)=0
We multiply parentheses
6m-10m-(-5(m+8)+10)-24+8=0
We calculate terms in parentheses: -(-5(m+8)+10), so:
-5(m+8)+10
We multiply parentheses
-5m-40+10
We add all the numbers together, and all the variables
-5m-30
Back to the equation:
-(-5m-30)
We add all the numbers together, and all the variables
-4m-(-5m-30)-16=0
We get rid of parentheses
-4m+5m+30-16=0
We add all the numbers together, and all the variables
m+14=0
We move all terms containing m to the left, all other terms to the right
m=-14

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