6(m-5)=(m+29)

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Solution for 6(m-5)=(m+29) equation: 



6(m-5)=(m+29)

We move all terms to the left:

6(m-5)-((m+29))=0

We multiply parentheses

6m-((m+29))-30=0



We calculate terms in parentheses: -((m+29)), so:

(m+29)

We get rid of parentheses

m+29

Back to the equation:

-(m+29)



We get rid of parentheses

6m-m-29-30=0

We add all the numbers together, and all the variables

5m-59=0

We move all terms containing m to the left, all other terms to the right

5m=59

m=59/5

m=11+4/5

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