6(n+1)=2(2n-4)

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Solution for 6(n+1)=2(2n-4) equation: 



6(n+1)=2(2n-4)

We move all terms to the left:

6(n+1)-(2(2n-4))=0

We multiply parentheses

6n-(2(2n-4))+6=0



We calculate terms in parentheses: -(2(2n-4)), so:

2(2n-4)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

6n-4n+8+6=0

We add all the numbers together, and all the variables

2n+14=0

We move all terms containing n to the left, all other terms to the right

2n=-14

n=-14/2

n=-7

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