6(n+1)=4(n+3)

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Solution for 6(n+1)=4(n+3) equation: 



6(n+1)=4(n+3)

We move all terms to the left:

6(n+1)-(4(n+3))=0

We multiply parentheses

6n-(4(n+3))+6=0



We calculate terms in parentheses: -(4(n+3)), so:

4(n+3)

We multiply parentheses

4n+12

Back to the equation:

-(4n+12)



We get rid of parentheses

6n-4n-12+6=0

We add all the numbers together, and all the variables

2n-6=0

We move all terms containing n to the left, all other terms to the right

2n=6

n=6/2

n=3

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