6(n+2)+3(3n-5)=57

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Solution for 6(n+2)+3(3n-5)=57 equation:


Simplifying
6(n + 2) + 3(3n + -5) = 57

Reorder the terms:
6(2 + n) + 3(3n + -5) = 57
(2 * 6 + n * 6) + 3(3n + -5) = 57
(12 + 6n) + 3(3n + -5) = 57

Reorder the terms:
12 + 6n + 3(-5 + 3n) = 57
12 + 6n + (-5 * 3 + 3n * 3) = 57
12 + 6n + (-15 + 9n) = 57

Reorder the terms:
12 + -15 + 6n + 9n = 57

Combine like terms: 12 + -15 = -3
-3 + 6n + 9n = 57

Combine like terms: 6n + 9n = 15n
-3 + 15n = 57

Solving
-3 + 15n = 57

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 15n = 57 + 3

Combine like terms: -3 + 3 = 0
0 + 15n = 57 + 3
15n = 57 + 3

Combine like terms: 57 + 3 = 60
15n = 60

Divide each side by '15'.
n = 4

Simplifying
n = 4

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