6(n+2)-4=5(2-n)

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Solution for 6(n+2)-4=5(2-n) equation: 



6(n+2)-4=5(2-n)

We move all terms to the left:

6(n+2)-4-(5(2-n))=0

We add all the numbers together, and all the variables

6(n+2)-(5(-1n+2))-4=0

We multiply parentheses

6n-(5(-1n+2))+12-4=0



We calculate terms in parentheses: -(5(-1n+2)), so:

5(-1n+2)

We multiply parentheses

-5n+10

Back to the equation:

-(-5n+10)



We add all the numbers together, and all the variables

6n-(-5n+10)+8=0

We get rid of parentheses

6n+5n-10+8=0

We add all the numbers together, and all the variables

11n-2=0

We move all terms containing n to the left, all other terms to the right

11n=2

n=2/11

n=2/11

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