6(n+3)+5=4n+27

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Solution for 6(n+3)+5=4n+27 equation: 



6(n+3)+5=4n+27

We move all terms to the left:

6(n+3)+5-(4n+27)=0

We multiply parentheses

6n-(4n+27)+18+5=0

We get rid of parentheses

6n-4n-27+18+5=0

We add all the numbers together, and all the variables

2n-4=0

We move all terms containing n to the left, all other terms to the right

2n=4

n=4/2

n=2

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