6(n+3)=-2(n-1)

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Solution for 6(n+3)=-2(n-1) equation: 



6(n+3)=-2(n-1)

We move all terms to the left:

6(n+3)-(-2(n-1))=0

We multiply parentheses

6n-(-2(n-1))+18=0



We calculate terms in parentheses: -(-2(n-1)), so:

-2(n-1)

We multiply parentheses

-2n+2

Back to the equation:

-(-2n+2)



We get rid of parentheses

6n+2n-2+18=0

We add all the numbers together, and all the variables

8n+16=0

We move all terms containing n to the left, all other terms to the right

8n=-16

n=-16/8

n=-2

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