6(n+3)=2n-n

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Solution for 6(n+3)=2n-n equation: 



6(n+3)=2n-n

We move all terms to the left:

6(n+3)-(2n-n)=0

We add all the numbers together, and all the variables

6(n+3)-(+n)=0

We multiply parentheses

6n-(+n)+18=0

We get rid of parentheses

6n-n+18=0

We add all the numbers together, and all the variables

5n+18=0

We move all terms containing n to the left, all other terms to the right

5n=-18

n=-18/5

n=-3+3/5

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