6(n+3)=6(n+2)+6

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Solution for 6(n+3)=6(n+2)+6 equation: 



6(n+3)=6(n+2)+6

We move all terms to the left:

6(n+3)-(6(n+2)+6)=0

We multiply parentheses

6n-(6(n+2)+6)+18=0



We calculate terms in parentheses: -(6(n+2)+6), so:

6(n+2)+6

We multiply parentheses

6n+12+6

We add all the numbers together, and all the variables

6n+18

Back to the equation:

-(6n+18)



We get rid of parentheses

6n-6n-18+18=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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