6(n+3)=n12-12

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Solution for 6(n+3)=n12-12 equation: 



6(n+3)=n12-12

We move all terms to the left:

6(n+3)-(n12-12)=0

We add all the numbers together, and all the variables

-(+n^12-12)+6(n+3)=0

We multiply parentheses

-(+n^12-12)+6n+18=0

We get rid of parentheses

-n^12+6n+12+18=0

We do not support enpression: n^12

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