6(n+5)=4(n+1)

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Solution for 6(n+5)=4(n+1) equation: 



6(n+5)=4(n+1)

We move all terms to the left:

6(n+5)-(4(n+1))=0

We multiply parentheses

6n-(4(n+1))+30=0



We calculate terms in parentheses: -(4(n+1)), so:

4(n+1)

We multiply parentheses

4n+4

Back to the equation:

-(4n+4)



We get rid of parentheses

6n-4n-4+30=0

We add all the numbers together, and all the variables

2n+26=0

We move all terms containing n to the left, all other terms to the right

2n=-26

n=-26/2

n=-13

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