6(n-1)=2(n+1)=2

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Solution for 6(n-1)=2(n+1)=2 equation: 



6(n-1)=2(n+1)=2

We move all terms to the left:

6(n-1)-(2(n+1))=0

We multiply parentheses

6n-(2(n+1))-6=0



We calculate terms in parentheses: -(2(n+1)), so:

2(n+1)

We multiply parentheses

2n+2

Back to the equation:

-(2n+2)



We get rid of parentheses

6n-2n-2-6=0

We add all the numbers together, and all the variables

4n-8=0

We move all terms containing n to the left, all other terms to the right

4n=8

n=8/4

n=2

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