6(n-1)=3(n+3)

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Solution for 6(n-1)=3(n+3) equation: 



6(n-1)=3(n+3)

We move all terms to the left:

6(n-1)-(3(n+3))=0

We multiply parentheses

6n-(3(n+3))-6=0



We calculate terms in parentheses: -(3(n+3)), so:

3(n+3)

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We get rid of parentheses

6n-3n-9-6=0

We add all the numbers together, and all the variables

3n-15=0

We move all terms containing n to the left, all other terms to the right

3n=15

n=15/3

n=5

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