6(n-1)=5(n+3)

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Solution for 6(n-1)=5(n+3) equation: 



6(n-1)=5(n+3)

We move all terms to the left:

6(n-1)-(5(n+3))=0

We multiply parentheses

6n-(5(n+3))-6=0



We calculate terms in parentheses: -(5(n+3)), so:

5(n+3)

We multiply parentheses

5n+15

Back to the equation:

-(5n+15)



We get rid of parentheses

6n-5n-15-6=0

We add all the numbers together, and all the variables

n-21=0

We move all terms containing n to the left, all other terms to the right

n=21

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