6(n-2)-(4-7n)=12n

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Solution for 6(n-2)-(4-7n)=12n equation: 



6(n-2)-(4-7n)=12n

We move all terms to the left:

6(n-2)-(4-7n)-(12n)=0

We add all the numbers together, and all the variables

6(n-2)-(-7n+4)-12n=0

We add all the numbers together, and all the variables

-12n+6(n-2)-(-7n+4)=0

We multiply parentheses

-12n+6n-(-7n+4)-12=0

We get rid of parentheses

-12n+6n+7n-4-12=0

We add all the numbers together, and all the variables

n-16=0

We move all terms containing n to the left, all other terms to the right

n=16

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