6(n-2)-8=22+4(2-n)

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Solution for 6(n-2)-8=22+4(2-n) equation: 



6(n-2)-8=22+4(2-n)

We move all terms to the left:

6(n-2)-8-(22+4(2-n))=0

We add all the numbers together, and all the variables

6(n-2)-(22+4(-1n+2))-8=0

We multiply parentheses

6n-(22+4(-1n+2))-12-8=0



We calculate terms in parentheses: -(22+4(-1n+2)), so:

22+4(-1n+2)

determiningTheFunctionDomain
4(-1n+2)+22

We multiply parentheses

-4n+8+22

We add all the numbers together, and all the variables

-4n+30

Back to the equation:

-(-4n+30)



We add all the numbers together, and all the variables

6n-(-4n+30)-20=0

We get rid of parentheses

6n+4n-30-20=0

We add all the numbers together, and all the variables

10n-50=0

We move all terms containing n to the left, all other terms to the right

10n=50

n=50/10

n=5

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