6(n-3)+2=2n+4(n-1)

Solution for 6(n-3)+2=2n+4(n-1) equation:

Simplifying
6(n + -3) + 2 = 2n + 4(n + -1)

Reorder the terms:
6(-3 + n) + 2 = 2n + 4(n + -1)
(-3 * 6 + n * 6) + 2 = 2n + 4(n + -1)
(-18 + 6n) + 2 = 2n + 4(n + -1)

Reorder the terms:
-18 + 2 + 6n = 2n + 4(n + -1)

Combine like terms: -18 + 2 = -16
-16 + 6n = 2n + 4(n + -1)

Reorder the terms:
-16 + 6n = 2n + 4(-1 + n)
-16 + 6n = 2n + (-1 * 4 + n * 4)
-16 + 6n = 2n + (-4 + 4n)

Reorder the terms:
-16 + 6n = -4 + 2n + 4n

Combine like terms: 2n + 4n = 6n
-16 + 6n = -4 + 6n

Add '-6n' to each side of the equation.
-16 + 6n + -6n = -4 + 6n + -6n

Combine like terms: 6n + -6n = 0
-16 + 0 = -4 + 6n + -6n
-16 = -4 + 6n + -6n

Combine like terms: 6n + -6n = 0
-16 = -4 + 0
-16 = -4

Solving
-16 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.