6(n-3)-2n=20

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Solution for 6(n-3)-2n=20 equation: 



6(n-3)-2n=20

We move all terms to the left:

6(n-3)-2n-(20)=0

We add all the numbers together, and all the variables

-2n+6(n-3)-20=0

We multiply parentheses

-2n+6n-18-20=0

We add all the numbers together, and all the variables

4n-38=0

We move all terms containing n to the left, all other terms to the right

4n=38

n=38/4

n=9+1/2

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