6(n-3)2-n=10

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Solution for 6(n-3)2-n=10 equation: 



6(n-3)2-n=10

We move all terms to the left:

6(n-3)2-n-(10)=0

We add all the numbers together, and all the variables

-1n+6(n-3)2-10=0

We multiply parentheses

-1n+12n-36-10=0

We add all the numbers together, and all the variables

11n-46=0

We move all terms containing n to the left, all other terms to the right

11n=46

n=46/11

n=4+2/11

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