6(n-3)=4(n-21)

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Solution for 6(n-3)=4(n-21) equation: 



6(n-3)=4(n-21)

We move all terms to the left:

6(n-3)-(4(n-21))=0

We multiply parentheses

6n-(4(n-21))-18=0



We calculate terms in parentheses: -(4(n-21)), so:

4(n-21)

We multiply parentheses

4n-84

Back to the equation:

-(4n-84)



We get rid of parentheses

6n-4n+84-18=0

We add all the numbers together, and all the variables

2n+66=0

We move all terms containing n to the left, all other terms to the right

2n=-66

n=-66/2

n=-33

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