6(n-5)=-3(2n+2)

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Solution for 6(n-5)=-3(2n+2) equation: 



6(n-5)=-3(2n+2)

We move all terms to the left:

6(n-5)-(-3(2n+2))=0

We multiply parentheses

6n-(-3(2n+2))-30=0



We calculate terms in parentheses: -(-3(2n+2)), so:

-3(2n+2)

We multiply parentheses

-6n-6

Back to the equation:

-(-6n-6)



We get rid of parentheses

6n+6n+6-30=0

We add all the numbers together, and all the variables

12n-24=0

We move all terms containing n to the left, all other terms to the right

12n=24

n=24/12

n=2

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