6(n-7)=2(n-14)

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Solution for 6(n-7)=2(n-14) equation: 



6(n-7)=2(n-14)

We move all terms to the left:

6(n-7)-(2(n-14))=0

We multiply parentheses

6n-(2(n-14))-42=0



We calculate terms in parentheses: -(2(n-14)), so:

2(n-14)

We multiply parentheses

2n-28

Back to the equation:

-(2n-28)



We get rid of parentheses

6n-2n+28-42=0

We add all the numbers together, and all the variables

4n-14=0

We move all terms containing n to the left, all other terms to the right

4n=14

n=14/4

n=3+1/2

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