6(p+2)=5(p-3)+p+27

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Solution for 6(p+2)=5(p-3)+p+27 equation: 



6(p+2)=5(p-3)+p+27

We move all terms to the left:

6(p+2)-(5(p-3)+p+27)=0

We multiply parentheses

6p-(5(p-3)+p+27)+12=0



We calculate terms in parentheses: -(5(p-3)+p+27), so:

5(p-3)+p+27

We add all the numbers together, and all the variables

p+5(p-3)+27

We multiply parentheses

p+5p-15+27

We add all the numbers together, and all the variables

6p+12

Back to the equation:

-(6p+12)



We get rid of parentheses

6p-6p-12+12=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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