6(p+3)=5(2-p)+78-12

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Solution for 6(p+3)=5(2-p)+78-12 equation: 



6(p+3)=5(2-p)+78-12

We move all terms to the left:

6(p+3)-(5(2-p)+78-12)=0

We add all the numbers together, and all the variables

6(p+3)-(5(-1p+2)+78-12)=0

We multiply parentheses

6p-(5(-1p+2)+78-12)+18=0



We calculate terms in parentheses: -(5(-1p+2)+78-12), so:

5(-1p+2)+78-12

We add all the numbers together, and all the variables

5(-1p+2)+66

We multiply parentheses

-5p+10+66

We add all the numbers together, and all the variables

-5p+76

Back to the equation:

-(-5p+76)



We get rid of parentheses

6p+5p-76+18=0

We add all the numbers together, and all the variables

11p-58=0

We move all terms containing p to the left, all other terms to the right

11p=58

p=58/11

p=5+3/11

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