6(p-1)-p=2(p+1)+p+1

Solution for 6(p-1)-p=2(p+1)+p+1 equation:

6(p-1)-p=2(p+1)+p+1

We move all terms to the left:

6(p-1)-p-(2(p+1)+p+1)=0

We add all the numbers together, and all the variables

-1p+6(p-1)-(2(p+1)+p+1)=0

We multiply parentheses

-1p+6p-(2(p+1)+p+1)-6=0


We calculate terms in parentheses: -(2(p+1)+p+1), so:

2(p+1)+p+1

We add all the numbers together, and all the variables

p+2(p+1)+1

We multiply parentheses

p+2p+2+1

We add all the numbers together, and all the variables

3p+3

Back to the equation:

-(3p+3)


We add all the numbers together, and all the variables

5p-(3p+3)-6=0

We get rid of parentheses

5p-3p-3-6=0

We add all the numbers together, and all the variables

2p-9=0

We move all terms containing p to the left, all other terms to the right

2p=9

p=9/2

p=4+1/2