6(q-10)=4(5-q)

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Solution for 6(q-10)=4(5-q) equation: 



6(q-10)=4(5-q)

We move all terms to the left:

6(q-10)-(4(5-q))=0

We add all the numbers together, and all the variables

6(q-10)-(4(-1q+5))=0

We multiply parentheses

6q-(4(-1q+5))-60=0



We calculate terms in parentheses: -(4(-1q+5)), so:

4(-1q+5)

We multiply parentheses

-4q+20

Back to the equation:

-(-4q+20)



We get rid of parentheses

6q+4q-20-60=0

We add all the numbers together, and all the variables

10q-80=0

We move all terms containing q to the left, all other terms to the right

10q=80

q=80/10

q=8

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