6(q-4)-3(q-2)=12

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Solution for 6(q-4)-3(q-2)=12 equation:


Simplifying
6(q + -4) + -3(q + -2) = 12

Reorder the terms:
6(-4 + q) + -3(q + -2) = 12
(-4 * 6 + q * 6) + -3(q + -2) = 12
(-24 + 6q) + -3(q + -2) = 12

Reorder the terms:
-24 + 6q + -3(-2 + q) = 12
-24 + 6q + (-2 * -3 + q * -3) = 12
-24 + 6q + (6 + -3q) = 12

Reorder the terms:
-24 + 6 + 6q + -3q = 12

Combine like terms: -24 + 6 = -18
-18 + 6q + -3q = 12

Combine like terms: 6q + -3q = 3q
-18 + 3q = 12

Solving
-18 + 3q = 12

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 3q = 12 + 18

Combine like terms: -18 + 18 = 0
0 + 3q = 12 + 18
3q = 12 + 18

Combine like terms: 12 + 18 = 30
3q = 30

Divide each side by '3'.
q = 10

Simplifying
q = 10

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