6(q-5)=12+3q

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Solution for 6(q-5)=12+3q equation: 



6(q-5)=12+3q

We move all terms to the left:

6(q-5)-(12+3q)=0

We add all the numbers together, and all the variables

6(q-5)-(3q+12)=0

We multiply parentheses

6q-(3q+12)-30=0

We get rid of parentheses

6q-3q-12-30=0

We add all the numbers together, and all the variables

3q-42=0

We move all terms containing q to the left, all other terms to the right

3q=42

q=42/3

q=14

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