6(r+1)=-2(1-2r)-6

Solution for 6(r+1)=-2(1-2r)-6 equation:

6(r+1)=-2(1-2r)-6

We move all terms to the left:

6(r+1)-(-2(1-2r)-6)=0

We add all the numbers together, and all the variables

6(r+1)-(-2(-2r+1)-6)=0

We multiply parentheses

6r-(-2(-2r+1)-6)+6=0


We calculate terms in parentheses: -(-2(-2r+1)-6), so:

-2(-2r+1)-6

We multiply parentheses

4r-2-6

We add all the numbers together, and all the variables

4r-8

Back to the equation:

-(4r-8)


We get rid of parentheses

6r-4r+8+6=0

We add all the numbers together, and all the variables

2r+14=0

We move all terms containing r to the left, all other terms to the right

2r=-14

r=-14/2

r=-7