6(r+2)+2(2r-5)=2

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Solution for 6(r+2)+2(2r-5)=2 equation: 



6(r+2)+2(2r-5)=2

We move all terms to the left:

6(r+2)+2(2r-5)-(2)=0

We multiply parentheses

6r+4r+12-10-2=0

We add all the numbers together, and all the variables

10r=0

r=0/10

r=0

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