6(r+3)=3(6+2r)

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Solution for 6(r+3)=3(6+2r) equation:



6(r+3)=3(6+2r)
We move all terms to the left:
6(r+3)-(3(6+2r))=0
We add all the numbers together, and all the variables
6(r+3)-(3(2r+6))=0
We multiply parentheses
6r-(3(2r+6))+18=0
We calculate terms in parentheses: -(3(2r+6)), so:
3(2r+6)
We multiply parentheses
6r+18
Back to the equation:
-(6r+18)
We get rid of parentheses
6r-6r-18+18=0
We add all the numbers together, and all the variables
=0
r=0/1
r=0

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