6(r-3)-5(r-1)=2(r+4)

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Solution for 6(r-3)-5(r-1)=2(r+4) equation: 



6(r-3)-5(r-1)=2(r+4)

We move all terms to the left:

6(r-3)-5(r-1)-(2(r+4))=0

We multiply parentheses

6r-5r-(2(r+4))-18+5=0



We calculate terms in parentheses: -(2(r+4)), so:

2(r+4)

We multiply parentheses

2r+8

Back to the equation:

-(2r+8)



We add all the numbers together, and all the variables

r-(2r+8)-13=0

We get rid of parentheses

r-2r-8-13=0

We add all the numbers together, and all the variables

-1r-21=0

We move all terms containing r to the left, all other terms to the right

-r=21

r=21/-1

r=-21

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