6(r-4)+1=r+17

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Solution for 6(r-4)+1=r+17 equation:



6(r-4)+1=r+17
We move all terms to the left:
6(r-4)+1-(r+17)=0
We multiply parentheses
6r-(r+17)-24+1=0
We get rid of parentheses
6r-r-17-24+1=0
We add all the numbers together, and all the variables
5r-40=0
We move all terms containing r to the left, all other terms to the right
5r=40
r=40/5
r=8

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