6(r-4)+1=r+17

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Solution for 6(r-4)+1=r+17 equation: 



6(r-4)+1=r+17

We move all terms to the left:

6(r-4)+1-(r+17)=0

We multiply parentheses

6r-(r+17)-24+1=0

We get rid of parentheses

6r-r-17-24+1=0

We add all the numbers together, and all the variables

5r-40=0

We move all terms containing r to the left, all other terms to the right

5r=40

r=40/5

r=8

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