6(r-7)+1=7(r+3)-23

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Solution for 6(r-7)+1=7(r+3)-23 equation: 



6(r-7)+1=7(r+3)-23

We move all terms to the left:

6(r-7)+1-(7(r+3)-23)=0

We multiply parentheses

6r-(7(r+3)-23)-42+1=0



We calculate terms in parentheses: -(7(r+3)-23), so:

7(r+3)-23

We multiply parentheses

7r+21-23

We add all the numbers together, and all the variables

7r-2

Back to the equation:

-(7r-2)



We add all the numbers together, and all the variables

6r-(7r-2)-41=0

We get rid of parentheses

6r-7r+2-41=0

We add all the numbers together, and all the variables

-1r-39=0

We move all terms containing r to the left, all other terms to the right

-r=39

r=39/-1

r=-39

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