6(r-7)+1=7(r+3)-25

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Solution for 6(r-7)+1=7(r+3)-25 equation: 



6(r-7)+1=7(r+3)-25

We move all terms to the left:

6(r-7)+1-(7(r+3)-25)=0

We multiply parentheses

6r-(7(r+3)-25)-42+1=0



We calculate terms in parentheses: -(7(r+3)-25), so:

7(r+3)-25

We multiply parentheses

7r+21-25

We add all the numbers together, and all the variables

7r-4

Back to the equation:

-(7r-4)



We add all the numbers together, and all the variables

6r-(7r-4)-41=0

We get rid of parentheses

6r-7r+4-41=0

We add all the numbers together, and all the variables

-1r-37=0

We move all terms containing r to the left, all other terms to the right

-r=37

r=37/-1

r=-37

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